TTTR1323 – MATEMATIK 2
SEMESTER 2 ( 2011 / 2012 )
PROJECT PART
LECTURER: PUAN NORAIDAH BT. SAHARI
Group Members:
1. LIM MEI TING TH A138329
2. WONG CHEAU
LING TH A138531
3. GAN POH YEE TH A138507
4. TAN CHU YING TH A138513
5. TAN POI TING TH A138519
TR1323 Students project
GROUP 4
Meeting Minutes 1
WONG CHEAU LING A138531
TAN CHU YING A138513
TAN POI TING A138519
LIM MEI TING
A138329
GAN POH YEE A138507
27th Feb:
- Find the group member of five for TR1323 Students project.
-Downloaded the project from spin.
-Interpreted and discussed about the constructive reasons why we are
learning
TR1323
28th Feb:
-Find the information from internet and reference books.
-Centralized the information we had found
out.
-Arranged all the information in proper arrangement so easy to
understand and read.
-Typing all the information into Microsoft words.
29th Feb: -Send all the documents we had
donned to all group members.
-Print out the documents into hard copy.
-Pass
up the hard copy to ours lecturer.
TR1323 Students project
GROUP 4
Meeting Minutes 2
WONG CHEAU
LING A138531
TAN CHU
YING A138513
TAN POI
TING A138519
LIM MEI TING
A138329
GAN POH YEE
A138507
5th March: -Discussing
the typed of product we want to choose.
-Starts finding the products.
10th March: -Capture the products.
-Draw
the outline.
-Discuss the function used.
-Surfing the internet to get more information of the function.
18th March:
-Compile the findings.
-Complete the project paper.
TR1323 Students project
GROUP 4
Meeting Minutes 3
WONG CHEAU
LING A138531
TAN CHU
YING A138513
TAN POI
TING A138519
LIM MEI TING A138329
GAN POH YEE
A138507
4th April: -
Discussing about what is mean by cross section of products.
- Discussing what is mean by
finding area of actual products.
8th April:-Surfing the internet to get more
information about the way to find out the volume and cross section.
- give out the
idea how to find the cross section and volume by using integration.
14th April:
-Start calculates the value of volume and cross section by different way.
20th April:-Compile the findings.
-Complete the
project paper.
Definitions of Multimedia
Multimedia is media and content that uses a combination of different content
forms. Multimedia includes a combination of text, audio, still images, animation, video, or interactivity content forms. Multimedia is usually
recorded and played, displayed or accessed by information
content processing devices,
such as computerized and electronic devices, but can also be part of a live
performance. Multimedia also describes electronic
media devices used to store
and experience multimedia content. Multimedia is distinguished from mixed media in fine art; by
including audio, for example, it has a broader scope. The term "rich
media" is synonymous for interactive
multimedia. Hypermedia can be considered one particular
multimedia application.
Classifications
of Multimedia
Multimedia
may be broadly divided into linear and non-linear categories. Linear active content
progresses without any navigational control for the viewer such as a cinema presentation.
Non-linear user interactivity to control
progress as used with a video game or used in
self-paced computer based training. Hypermedia(a computer-based information retrieval system that
enables a user to gain or provide access to texts, audio and video recordings,
photographs and computer graphics related to a particular subject) is an example of non-linear content. Multimedia presentations can be live or
recorded. A recorded presentation may allow interactivity via a navigation system. A live multimedia presentation may allow interactivity via
an interaction with the presenter or performer.
Figure 1: Model of the cup at x-axis
Figure 2: Outline of
the cup
Equation of function for the selected product
Using (0, 2.6) and (11.5, 3.8) to the equation
(y - 2.6)(11.5)= 1.2x
y=
The cross‐section and volume of the product
Figure 1:
Cross section for one part of cup
Figure 2:
Cross section of Circle
Area of one
part of the cup =
=
=
=
= 6.9 + 2.99
= 36.8cm2
Cross section of cup = Area
of one part of the cup * 3
=
36.8 cm2 * 3
=
110.4 cm2
Cross
section of circle =
=
(2.6)2
=
10.619 cm2
Total cross section = Cross section of cup + Cross section of circle
=
110.4 cm2 + 10.619 cm2
= 121.019 cm2
Figure 2: Volume of the cup
Figure 3: Interior volume of the cup
Volume of A =
=
=
=
=
=
=
Volume of B =
=
=
=
=
=
= 348.472
Volume of cup = Volume
of A – Volume of B
=
– 348.472
= 25.82
The Actual Product
Area of object = 122 cm2
Volume of object = 242 cm2 x 0.1 cm2
= 24.2 cm3
Conclusion
The
actual volume of paper cup is 24.2cm3 and the volume of paper cup by
using calculation is 25.82cm3, (25.82c
–
24.2c
) there is 1.62c
This may influence by the thickness of the paper cup that we ignored in
calculation.
Final Conclusion
In TR1323(Calculus), we
have to finish a project regarding the topic of calculus. From Part I, we have
given the constructive reasons why we need to learn TR1323. Hence, we know that
the definition of multimedia and examples about multimedia to support our
definition. Besides that, we also show a relevancy of TR1323 to the multimedia
and give an example. Thus, we can know that multimedia is relevant to TR1323.
From
Part II, we have chosen a product which is a paper cup. We have captured the
paper cup for the calculation uses in next calculation. The outline of paper
cup is drawn in order to identify the shape using to combined become a paper
cup. The shape or outline of the paper cup is modeled by using single function.
We use the function
and the value or length of paper cup (0, 2.6) and (11.5, 3.8) to form a
new function. The function is
y=
From
Part III, we have used the knowledge that learnt in TR1323 to find the cross section
and volume of the paper cup. First, we
use the formulae integration
to calculate the area of one part of the paper cup. We assumed that the
body of paper cup consists of 3 parts. So, we need to calculate one part of the
paper cup then multiple with 3. Therefore, the area of one part of the paper
cup is 36.8 cm2 and multiple with 3 is 110.4cm2. After
that, we have to sum up the cross section of body paper cup and the cross
section of circle. Next, we use formula
to calculate the value of cross section of the paper cup. The value
calculated is 10.619cm2. We get the values of 121.019cm2.
After that, we use the formulae of volume to
calculate the volume of paper cup. We assigned two part of volume which is
volume A and volume B. The formulae for volume A is
while the formulae of volume B is
.
Then, we subtract the volume of A (
from volume B (348.472
) and get the volume of paper cup which
is 25.82cm3.
To verify the answers
that we calculated for area of paper cup and volume of paper cup, we use a
graph. We draw the actual outline of paper cup in the graph (1cm x 1cm) to
count the units of outline of paper cup in the graph. After counted, we get 122
units which are 122cm2 for the area of paper cup. While, 242 units
which is 242cm2 and this value is multiple with 0.1cm2 to
get the volume of paper cup which is 24.2cm3.
By comparison, the
actual area of paper cup is 122cm2 and the answer we calculated by
formulae is 110.4cm2. The difference of both values is +11.6cm2.
For the actual volume of paper cup we count, we have the volume of 24.2cm3
and the answer we calculated by formulae is 25.82cm3. The difference
of both of the values is -1.62cm3.
In conclusions, we are
able to choose an object to calculate the area and volume of the objects. Then,
we also able to compare the actual value of objects and the values that
calculate by using the formulae. Besides that, we have relevant the multimedia
and TR13223 in this project successfully.
